python-algorithm
leetcode 290. Word Pattern
무적김두칠
2022. 3. 17. 11:14
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class Solution:
def wordPattern(self, pattern: str, s: str) -> bool:
s=list(s.split())
checkList=[]
checkPattern=[]
ans=''
ansPattern=''
for i in s:
if i in checkList :
pass
else:
checkList.append(i)
ans += chr(checkList.index(i) + 97)
for i in pattern:
if i in checkPattern :
pass
else:
checkPattern.append(i)
ansPattern += chr(checkPattern.index(i) + 97)
if ansPattern==ans: return True
else: return False
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cs |
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