Leetcode 1365. How Many Numbers Are Smaller Than the Current Number

class Solution:
    def smallerNumbersThanCurrent(self, nums: List[int]) -> List[int]:
        ans=[]
        for i in range(len(nums)):
            tmp=0
            for j in range(len(nums)):
                if nums[i]>nums[j] :tmp+=1
            ans.append(tmp)
        return ans