python-algorithm
leetcode 2032. Two Out of Three
무적김두칠
2022. 3. 21. 11:16
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class Solution:
def twoOutOfThree(self, nums1: List[int], nums2: List[int], nums3: List[int]) -> List[int]:
ans=[]
for i in nums1:
if i in nums2 or i in nums3: ans.append(i)
for i in nums2:
if i in nums1 or i in nums3: ans.append(i)
for i in nums3:
if i in nums2 or i in nums1: ans.append(i)
ans= list(set(ans))
return ans
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cs |
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