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python-algorithm

leetcode 2057. Smallest Index With Equal Value

by 무적김두칠 2022. 3. 21.

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class Solution:
    def smallestEqual(self, nums: List[int]) -> int:
        flag=0
        for i in range(len(nums)):
            if i%10==nums[i] : ans=i; flag=1; break
        if flag==0 : ans=-1
        return ans
cs
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