leetcode 844. Backspace String Compare

def sol(s):
    for i in range(len(s)):
        if '#' in s :
            if s[0]=='#' : s=s[1:]
            else :
                s = s[:s.find('#') - 1] + s[s.find('#') + 1:]
        else : break
    return s
 
class Solution:
    def backspaceCompare(self, s: str, t: str) -> bool:
        if sol(s)== sol(t) : return True
        else: return False